WebOct 4, 2024 · Try this: import { initializeApp } from 'firebase/app'; const app = initializeApp ( {}); getDatabaseFunc = () => { const db = getDatabase (); const ref = ref (db, "data/") } change the name of the main function to getDatabaseFunc or any other name different from getDatabase () to prevent overriding Share Improve this answer Follow WebJul 26, 2024 · Node and ts-node compiles without problem, but when creating instance by require i get ReferenceError: Cannot access 'Object' before initialization. Object is main abstract class being extended by Element which is then extended by element type. Class is initialized without problem if there is no Object class being extended, but Object class …
Cannot access
WebMar 28, 2024 · The JavaScript exception "can't access lexical declaration ` variable ' before initialization" occurs when a lexical variable was accessed before it was initialized. This happens within any block statement, when let or const variables are accessed before the line in which they are declared is executed. Message WebMay 25, 2024 · 2. You named your variable the same as your function and the compiler is confused: let loginTodayResult = await loginToday (); Share. Follow. answered May 25, 2024 at 14:43. tymeJV. 104k 14 161 157. Add a comment. church paino book 1
[SOLVED] Cannot Access Before Initialization Error in JavaScript
WebFeb 8, 2024 · The examples clearly show how to solve the problem of loops. The main thing to understand is that module dependencies must be used implicitly during initialization or used after initialization. ./run_script.js. export B from './B.js'; // the first, since it has a dependency A ( extends A) export A from './A.js'; WebMay 27, 2024 · 1 Answer Sorted by: 33 When you assign variables using $: you cannot assign them as part of other variables declared using let, const, or var. When you do assignments using $:, you can only use them in other variables assigned using $:. In the code posted above, you need to change the following lines: Web1 Answer Sorted by: -1 Lets say a () method is written in ChestStage directly and not by heritance from Stage. It will be looking as the following: class ChestStage { a () { return new ChestStage (); } } That means you are trying to create an instance of ChestStage within method of ChestStage itself... That's impossible. Share Follow church pal 3